X+35=20x2

Solution for X+35=20x2 equation:

X+35=20X^2

We move all terms to the left:

X+35-(20X^2)=0

determiningTheFunctionDomain
-20X^2+X+35=0

a = -20; b = 1; c = +35;
Δ = b2-4ac
Δ = 12-4·(-20)·35
Δ = 2801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2801}}{2*-20}=\frac{-1-\sqrt{2801}}{-40}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2801}}{2*-20}=\frac{-1+\sqrt{2801}}{-40}
$