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X+3X(X-150)=1025
We move all terms to the left:
X+3X(X-150)-(1025)=0
We multiply parentheses
3X^2+X-450X-1025=0
We add all the numbers together, and all the variables
3X^2-449X-1025=0
a = 3; b = -449; c = -1025;
Δ = b2-4ac
Δ = -4492-4·3·(-1025)
Δ = 213901
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-449)-\sqrt{213901}}{2*3}=\frac{449-\sqrt{213901}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-449)+\sqrt{213901}}{2*3}=\frac{449+\sqrt{213901}}{6} $
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