X+3x+(3x+12)=96

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Solution for X+3x+(3x+12)=96 equation: 



X+3X+(3X+12)=96

We move all terms to the left:

X+3X+(3X+12)-(96)=0

We add all the numbers together, and all the variables

4X+(3X+12)-96=0

We get rid of parentheses

4X+3X+12-96=0

We add all the numbers together, and all the variables

7X-84=0

We move all terms containing X to the left, all other terms to the right

7X=84

X=84/7

X=12

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