X+3x+3=-(x+4)+(3x-2)

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Solution for X+3x+3=-(x+4)+(3x-2) equation:



X+3X+3=-(X+4)+(3X-2)
We move all terms to the left:
X+3X+3-(-(X+4)+(3X-2))=0
We add all the numbers together, and all the variables
4X-(-(X+4)+(3X-2))+3=0
We calculate terms in parentheses: -(-(X+4)+(3X-2)), so:
-(X+4)+(3X-2)
We get rid of parentheses
-X+3X-4-2
We add all the numbers together, and all the variables
2X-6
Back to the equation:
-(2X-6)
We get rid of parentheses
4X-2X+6+3=0
We add all the numbers together, and all the variables
2X+9=0
We move all terms containing X to the left, all other terms to the right
2X=-9
X=-9/2
X=-4+1/2

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