X+3x+3x-10+(3x-10)/2=495

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Solution for X+3x+3x-10+(3x-10)/2=495 equation: 



X+3X+3X-10+(3X-10)/2=495

We move all terms to the left:

X+3X+3X-10+(3X-10)/2-(495)=0

We add all the numbers together, and all the variables

7X+(3X-10)/2-505=0

We multiply all the terms by the denominator


7X*2+(3X-10)-505*2=0

We add all the numbers together, and all the variables

7X*2+(3X-10)-1010=0

Wy multiply elements

14X+(3X-10)-1010=0

We get rid of parentheses

14X+3X-10-1010=0

We add all the numbers together, and all the variables

17X-1020=0

We move all terms containing X to the left, all other terms to the right

17X=1020

X=1020/17

X=60

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