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X+3X^2=18
We move all terms to the left:
X+3X^2-(18)=0
a = 3; b = 1; c = -18;
Δ = b2-4ac
Δ = 12-4·3·(-18)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{217}}{2*3}=\frac{-1-\sqrt{217}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{217}}{2*3}=\frac{-1+\sqrt{217}}{6} $
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