X+4(3x+32)=12

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Solution for X+4(3x+32)=12 equation: 



X+4(3X+32)=12

We move all terms to the left:

X+4(3X+32)-(12)=0

We multiply parentheses

X+12X+128-12=0

We add all the numbers together, and all the variables

13X+116=0

We move all terms containing X to the left, all other terms to the right

13X=-116

X=-116/13

X=-8+12/13

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