X+4+1/3x=20

Solution for X+4+1/3x=20 equation:

X+4+1/3X=20

We move all terms to the left:

X+4+1/3X-(20)=0


Domain of the equation: 3X!=0

X!=0/3

X!=0

X∈R


We add all the numbers together, and all the variables

X+1/3X-16=0

We multiply all the terms by the denominator


X*3X-16*3X+1=0

Wy multiply elements

3X^2-48X+1=0

a = 3; b = -48; c = +1;
Δ = b2-4ac
Δ = -482-4·3·1
Δ = 2292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2292}=\sqrt{4*573}=\sqrt{4}*\sqrt{573}=2\sqrt{573}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-2\sqrt{573}}{2*3}=\frac{48-2\sqrt{573}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+2\sqrt{573}}{2*3}=\frac{48+2\sqrt{573}}{6}
$