X+4/3x-4=3

Solution for X+4/3x-4=3 equation:

X+4/3X-4=3

We move all terms to the left:

X+4/3X-4-(3)=0


Domain of the equation: 3X!=0

X!=0/3

X!=0

X∈R


We add all the numbers together, and all the variables

X+4/3X-7=0

We multiply all the terms by the denominator


X*3X-7*3X+4=0

Wy multiply elements

3X^2-21X+4=0

a = 3; b = -21; c = +4;
Δ = b2-4ac
Δ = -212-4·3·4
Δ = 393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{393}}{2*3}=\frac{21-\sqrt{393}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{393}}{2*3}=\frac{21+\sqrt{393}}{6}
$