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X+4/3X=420
We move all terms to the left:
X+4/3X-(420)=0
Domain of the equation: 3X!=0We multiply all the terms by the denominator
X!=0/3
X!=0
X∈R
X*3X-420*3X+4=0
Wy multiply elements
3X^2-1260X+4=0
a = 3; b = -1260; c = +4;
Δ = b2-4ac
Δ = -12602-4·3·4
Δ = 1587552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1587552}=\sqrt{16*99222}=\sqrt{16}*\sqrt{99222}=4\sqrt{99222}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1260)-4\sqrt{99222}}{2*3}=\frac{1260-4\sqrt{99222}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1260)+4\sqrt{99222}}{2*3}=\frac{1260+4\sqrt{99222}}{6} $
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