X+4/5x=126

Solution for X+4/5x=126 equation:

X+4/5X=126

We move all terms to the left:

X+4/5X-(126)=0


Domain of the equation: 5X!=0

X!=0/5

X!=0

X∈R


We multiply all the terms by the denominator


X*5X-126*5X+4=0

Wy multiply elements

5X^2-630X+4=0

a = 5; b = -630; c = +4;
Δ = b2-4ac
Δ = -6302-4·5·4
Δ = 396820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{396820}=\sqrt{4*99205}=\sqrt{4}*\sqrt{99205}=2\sqrt{99205}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-630)-2\sqrt{99205}}{2*5}=\frac{630-2\sqrt{99205}}{10}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-630)+2\sqrt{99205}}{2*5}=\frac{630+2\sqrt{99205}}{10}
$