X+4=2(3x-6-x)+x

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Solution for X+4=2(3x-6-x)+x equation: 



X+4=2(3X-6-X)+X

We move all terms to the left:

X+4-(2(3X-6-X)+X)=0

We add all the numbers together, and all the variables

X-(2(2X-6)+X)+4=0



We calculate terms in parentheses: -(2(2X-6)+X), so:

2(2X-6)+X

We add all the numbers together, and all the variables

X+2(2X-6)

We multiply parentheses

X+4X-12

We add all the numbers together, and all the variables

5X-12

Back to the equation:

-(5X-12)



We get rid of parentheses

X-5X+12+4=0

We add all the numbers together, and all the variables

-4X+16=0

We move all terms containing X to the left, all other terms to the right

-4X=-16

X=-16/-4

X=+4

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