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X+4X(X+13)=94
We move all terms to the left:
X+4X(X+13)-(94)=0
We multiply parentheses
4X^2+X+52X-94=0
We add all the numbers together, and all the variables
4X^2+53X-94=0
a = 4; b = 53; c = -94;
Δ = b2-4ac
Δ = 532-4·4·(-94)
Δ = 4313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-\sqrt{4313}}{2*4}=\frac{-53-\sqrt{4313}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+\sqrt{4313}}{2*4}=\frac{-53+\sqrt{4313}}{8} $
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