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X+4X^2=24
We move all terms to the left:
X+4X^2-(24)=0
a = 4; b = 1; c = -24;
Δ = b2-4ac
Δ = 12-4·4·(-24)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{385}}{2*4}=\frac{-1-\sqrt{385}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{385}}{2*4}=\frac{-1+\sqrt{385}}{8} $
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