X+5(3x+2)/2=102

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Solution for X+5(3x+2)/2=102 equation:



X+5(3X+2)/2=102
We move all terms to the left:
X+5(3X+2)/2-(102)=0
We multiply all the terms by the denominator
X*2+5(3X+2)-102*2=0
We add all the numbers together, and all the variables
X*2+5(3X+2)-204=0
We multiply parentheses
X*2+15X+10-204=0
Wy multiply elements
2X+15X+10-204=0
We add all the numbers together, and all the variables
17X-194=0
We move all terms containing X to the left, all other terms to the right
17X=194
X=194/17
X=11+7/17

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