X+5+5(2x-7)=x-4-2(2x+3)

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Solution for X+5+5(2x-7)=x-4-2(2x+3) equation: 



X+5+5(2X-7)=X-4-2(2X+3)

We move all terms to the left:

X+5+5(2X-7)-(X-4-2(2X+3))=0

We multiply parentheses

X+10X-(X-4-2(2X+3))-35+5=0



We calculate terms in parentheses: -(X-4-2(2X+3)), so:

X-4-2(2X+3)

determiningTheFunctionDomain
X-2(2X+3)-4

We multiply parentheses

X-4X-6-4

We add all the numbers together, and all the variables

-3X-10

Back to the equation:

-(-3X-10)



We add all the numbers together, and all the variables

11X-(-3X-10)-30=0

We get rid of parentheses

11X+3X+10-30=0

We add all the numbers together, and all the variables

14X-20=0

We move all terms containing X to the left, all other terms to the right

14X=20

X=20/14

X=1+3/7

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