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X+5/13X=48
We move all terms to the left:
X+5/13X-(48)=0
Domain of the equation: 13X!=0We multiply all the terms by the denominator
X!=0/13
X!=0
X∈R
X*13X-48*13X+5=0
Wy multiply elements
13X^2-624X+5=0
a = 13; b = -624; c = +5;
Δ = b2-4ac
Δ = -6242-4·13·5
Δ = 389116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{389116}=\sqrt{4*97279}=\sqrt{4}*\sqrt{97279}=2\sqrt{97279}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-624)-2\sqrt{97279}}{2*13}=\frac{624-2\sqrt{97279}}{26} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-624)+2\sqrt{97279}}{2*13}=\frac{624+2\sqrt{97279}}{26} $
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