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X+5/2X=9
We move all terms to the left:
X+5/2X-(9)=0
Domain of the equation: 2X!=0We multiply all the terms by the denominator
X!=0/2
X!=0
X∈R
X*2X-9*2X+5=0
Wy multiply elements
2X^2-18X+5=0
a = 2; b = -18; c = +5;
Δ = b2-4ac
Δ = -182-4·2·5
Δ = 284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{284}=\sqrt{4*71}=\sqrt{4}*\sqrt{71}=2\sqrt{71}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{71}}{2*2}=\frac{18-2\sqrt{71}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{71}}{2*2}=\frac{18+2\sqrt{71}}{4} $
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