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X+5/6X+10=43
We move all terms to the left:
X+5/6X+10-(43)=0
Domain of the equation: 6X!=0We add all the numbers together, and all the variables
X!=0/6
X!=0
X∈R
X+5/6X-33=0
We multiply all the terms by the denominator
X*6X-33*6X+5=0
Wy multiply elements
6X^2-198X+5=0
a = 6; b = -198; c = +5;
Δ = b2-4ac
Δ = -1982-4·6·5
Δ = 39084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{39084}=\sqrt{4*9771}=\sqrt{4}*\sqrt{9771}=2\sqrt{9771}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-198)-2\sqrt{9771}}{2*6}=\frac{198-2\sqrt{9771}}{12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-198)+2\sqrt{9771}}{2*6}=\frac{198+2\sqrt{9771}}{12} $
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