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X+5=14X^2
We move all terms to the left:
X+5-(14X^2)=0
determiningTheFunctionDomain -14X^2+X+5=0
a = -14; b = 1; c = +5;
Δ = b2-4ac
Δ = 12-4·(-14)·5
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{281}}{2*-14}=\frac{-1-\sqrt{281}}{-28} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{281}}{2*-14}=\frac{-1+\sqrt{281}}{-28} $
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