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X+6=5/4X
We move all terms to the left:
X+6-(5/4X)=0
Domain of the equation: 4X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+5/4X)+6=0
We get rid of parentheses
X-5/4X+6=0
We multiply all the terms by the denominator
X*4X+6*4X-5=0
Wy multiply elements
4X^2+24X-5=0
a = 4; b = 24; c = -5;
Δ = b2-4ac
Δ = 242-4·4·(-5)
Δ = 656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{656}=\sqrt{16*41}=\sqrt{16}*\sqrt{41}=4\sqrt{41}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{41}}{2*4}=\frac{-24-4\sqrt{41}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{41}}{2*4}=\frac{-24+4\sqrt{41}}{8} $
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