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X+7X^2=14
We move all terms to the left:
X+7X^2-(14)=0
a = 7; b = 1; c = -14;
Δ = b2-4ac
Δ = 12-4·7·(-14)
Δ = 393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{393}}{2*7}=\frac{-1-\sqrt{393}}{14} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{393}}{2*7}=\frac{-1+\sqrt{393}}{14} $
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