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X+9/2X+1=X-5/X
We move all terms to the left:
X+9/2X+1-(X-5/X)=0
Domain of the equation: 2X!=0
X!=0/2
X!=0
X∈R
Domain of the equation: X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X+9/2X-(+X-5/X)+1=0
We get rid of parentheses
X+9/2X-X+5/X+1=0
We calculate fractions
X-X+9X/2X^2+10X/2X^2+1=0
We add all the numbers together, and all the variables
9X/2X^2+10X/2X^2+1=0
We multiply all the terms by the denominator
9X+10X+1*2X^2=0
We add all the numbers together, and all the variables
19X+1*2X^2=0
Wy multiply elements
2X^2+19X=0
a = 2; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·2·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*2}=\frac{-38}{4} =-9+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*2}=\frac{0}{4} =0 $
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