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X+96/X=40
We move all terms to the left:
X+96/X-(40)=0
Domain of the equation: X!=0We multiply all the terms by the denominator
X∈R
X*X-40*X+96=0
We add all the numbers together, and all the variables
-40X+X*X+96=0
Wy multiply elements
X^2-40X+96=0
a = 1; b = -40; c = +96;
Δ = b2-4ac
Δ = -402-4·1·96
Δ = 1216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1216}=\sqrt{64*19}=\sqrt{64}*\sqrt{19}=8\sqrt{19}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-8\sqrt{19}}{2*1}=\frac{40-8\sqrt{19}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+8\sqrt{19}}{2*1}=\frac{40+8\sqrt{19}}{2} $
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