X+x+((x-2)/3)=144

Solution for X+x+((x-2)/3)=144 equation:

X+X+((X-2)/3)=144

We move all terms to the left:

X+X+((X-2)/3)-(144)=0

We add all the numbers together, and all the variables

2X+((X-2)/3)-144=0

We multiply all the terms by the denominator


2X*3)+((X-2)-144*3)=0

We add all the numbers together, and all the variables

2X*3)+((X-2)=0

Wy multiply elements

6X^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{12}=0$