X+x+1/3x=99

Solution for X+x+1/3x=99 equation:

X+X+1/3X=99

We move all terms to the left:

X+X+1/3X-(99)=0


Domain of the equation: 3X!=0

X!=0/3

X!=0

X∈R


We add all the numbers together, and all the variables

2X+1/3X-99=0

We multiply all the terms by the denominator


2X*3X-99*3X+1=0

Wy multiply elements

6X^2-297X+1=0

a = 6; b = -297; c = +1;
Δ = b2-4ac
Δ = -2972-4·6·1
Δ = 88185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-297)-\sqrt{88185}}{2*6}=\frac{297-\sqrt{88185}}{12}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-297)+\sqrt{88185}}{2*6}=\frac{297+\sqrt{88185}}{12}
$