X+x2+(X2+3)=88

Solution for X+x2+(X2+3)=88 equation:

X+X2+(X2+3)=88

We move all terms to the left:

X+X2+(X2+3)-(88)=0

We add all the numbers together, and all the variables

(+X^2+3)+X+X2-88=0

We add all the numbers together, and all the variables

X^2+(+X^2+3)+X-88=0

We get rid of parentheses

X^2+X^2+X+3-88=0

We add all the numbers together, and all the variables

2X^2+X-85=0

a = 2; b = 1; c = -85;
Δ = b2-4ac
Δ = 12-4·2·(-85)
Δ = 681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{681}}{2*2}=\frac{-1-\sqrt{681}}{4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{681}}{2*2}=\frac{-1+\sqrt{681}}{4}
$