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X+X+2/3X=17
We move all terms to the left:
X+X+2/3X-(17)=0
Domain of the equation: 3X!=0We add all the numbers together, and all the variables
X!=0/3
X!=0
X∈R
2X+2/3X-17=0
We multiply all the terms by the denominator
2X*3X-17*3X+2=0
Wy multiply elements
6X^2-51X+2=0
a = 6; b = -51; c = +2;
Δ = b2-4ac
Δ = -512-4·6·2
Δ = 2553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-\sqrt{2553}}{2*6}=\frac{51-\sqrt{2553}}{12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+\sqrt{2553}}{2*6}=\frac{51+\sqrt{2553}}{12} $
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