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X-(2X+1)=8+(3X+3)
We move all terms to the left:
X-(2X+1)-(8+(3X+3))=0
We get rid of parentheses
X-2X-(8+(3X+3))-1=0
We calculate terms in parentheses: -(8+(3X+3)), so:We add all the numbers together, and all the variables
8+(3X+3)
determiningTheFunctionDomain (3X+3)+8
We get rid of parentheses
3X+3+8
We add all the numbers together, and all the variables
3X+11
Back to the equation:
-(3X+11)
-1X-(3X+11)-1=0
We get rid of parentheses
-1X-3X-11-1=0
We add all the numbers together, and all the variables
-4X-12=0
We move all terms containing X to the left, all other terms to the right
-4X=12
X=12/-4
X=-3
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