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X-1(1/3X)=80
We move all terms to the left:
X-1(1/3X)-(80)=0
Domain of the equation: 3X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-1(+1/3X)-80=0
We multiply all the terms by the denominator
X*3X)-1(-80*3X)+1=0
Wy multiply elements
3X^2-240X=0
a = 3; b = -240; c = 0;
Δ = b2-4ac
Δ = -2402-4·3·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{57600}=240$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-240}{2*3}=\frac{0}{6} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+240}{2*3}=\frac{480}{6} =80 $
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