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X-1/3X=3500
We move all terms to the left:
X-1/3X-(3500)=0
Domain of the equation: 3X!=0We multiply all the terms by the denominator
X!=0/3
X!=0
X∈R
X*3X-3500*3X-1=0
Wy multiply elements
3X^2-10500X-1=0
a = 3; b = -10500; c = -1;
Δ = b2-4ac
Δ = -105002-4·3·(-1)
Δ = 110250012
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{110250012}=\sqrt{4*27562503}=\sqrt{4}*\sqrt{27562503}=2\sqrt{27562503}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10500)-2\sqrt{27562503}}{2*3}=\frac{10500-2\sqrt{27562503}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10500)+2\sqrt{27562503}}{2*3}=\frac{10500+2\sqrt{27562503}}{6} $
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