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X-1/5X-4/5X=0
Domain of the equation: 5X!=0We multiply all the terms by the denominator
X!=0/5
X!=0
X∈R
X*5X-1-4=0
We add all the numbers together, and all the variables
X*5X-5=0
Wy multiply elements
5X^2-5=0
a = 5; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·5·(-5)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*5}=\frac{-10}{10} =-1 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*5}=\frac{10}{10} =1 $
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