X-1/x-3=x+1/x-2

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Solution for X-1/x-3=x+1/x-2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

X-(1/x)-3 = x+1/x-2 // - x+1/x-2

X-x-(1/x)-(1/x)-3+2 = 0

X-x-x^-1-x^-1-3+2 = 0

-1*x^1-2*x^-1-1*x^0 = 0

(-1*x^2-1*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(-1*x^2-1*x^1-2*x^0) = 0

x^1

-x^2-x-2 = 0

-x^2-x-2 = 0

DELTA = (-1)^2-(-2*(-1)*4)

DELTA = -7

DELTA < 0

x in { } 

x belongs to the empty set

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