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X-11=3/4X-5
We move all terms to the left:
X-11-(3/4X-5)=0
Domain of the equation: 4X-5)!=0We get rid of parentheses
X∈R
X-3/4X+5-11=0
We multiply all the terms by the denominator
X*4X+5*4X-11*4X-3=0
Wy multiply elements
4X^2+20X-44X-3=0
We add all the numbers together, and all the variables
4X^2-24X-3=0
a = 4; b = -24; c = -3;
Δ = b2-4ac
Δ = -242-4·4·(-3)
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{39}}{2*4}=\frac{24-4\sqrt{39}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{39}}{2*4}=\frac{24+4\sqrt{39}}{8} $
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