X-2(12-0.5)=2(4-2x)+20

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Solution for X-2(12-0.5)=2(4-2x)+20 equation: 



X-2(12-0.5)=2(4-2X)+20

We move all terms to the left:

X-2(12-0.5)-(2(4-2X)+20)=0

We add all the numbers together, and all the variables

X-(2(-2X+4)+20)-2(11.5)=0

We add all the numbers together, and all the variables

X-(2(-2X+4)+20)-23=0



We calculate terms in parentheses: -(2(-2X+4)+20), so:

2(-2X+4)+20

We multiply parentheses

-4X+8+20

We add all the numbers together, and all the variables

-4X+28

Back to the equation:

-(-4X+28)



We get rid of parentheses

X+4X-28-23=0

We add all the numbers together, and all the variables

5X-51=0

We move all terms containing X to the left, all other terms to the right

5X=51

X=51/5

X=10+1/5

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