X-2(2x+1)=3-x+(-10)

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Solution for X-2(2x+1)=3-x+(-10) equation: 



X-2(2X+1)=3-X+(-10)

We move all terms to the left:

X-2(2X+1)-(3-X+(-10))=0

We multiply parentheses

X-4X-(3-X+(-10))-2=0



We calculate terms in parentheses: -(3-X+(-10)), so:

3-X+(-10)

determiningTheFunctionDomain
-X+3+(-10)

We add all the numbers together, and all the variables

-1X-7

Back to the equation:

-(-1X-7)



We add all the numbers together, and all the variables

-3X-(-1X-7)-2=0

We get rid of parentheses

-3X+1X+7-2=0

We add all the numbers together, and all the variables

-2X+5=0

We move all terms containing X to the left, all other terms to the right

-2X=-5

X=-5/-2

X=2+1/2

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