X-2(x-5)=3(x-2)-4

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Solution for X-2(x-5)=3(x-2)-4 equation: 



X-2(X-5)=3(X-2)-4

We move all terms to the left:

X-2(X-5)-(3(X-2)-4)=0

We multiply parentheses

X-2X-(3(X-2)-4)+10=0



We calculate terms in parentheses: -(3(X-2)-4), so:

3(X-2)-4

We multiply parentheses

3X-6-4

We add all the numbers together, and all the variables

3X-10

Back to the equation:

-(3X-10)



We add all the numbers together, and all the variables

-1X-(3X-10)+10=0

We get rid of parentheses

-1X-3X+10+10=0

We add all the numbers together, and all the variables

-4X+20=0

We move all terms containing X to the left, all other terms to the right

-4X=-20

X=-20/-4

X=+5

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