X-2=(y/10)+3

Solution for X-2=(y/10)+3 equation:

X-2=(X/10)+3

We move all terms to the left:

X-2-((X/10)+3)=0

We add all the numbers together, and all the variables

X-((+X/10)+3)-2=0

We multiply all the terms by the denominator


X*10)+3)-((+X-2*10)+3)=0

We add all the numbers together, and all the variables

X*10)+3)-((X-20)+3)=0

We add all the numbers together, and all the variables

X*10)+3)-((X=0

Wy multiply elements

10X^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{20}=0$