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X-2=1/5X
We move all terms to the left:
X-2-(1/5X)=0
Domain of the equation: 5X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+1/5X)-2=0
We get rid of parentheses
X-1/5X-2=0
We multiply all the terms by the denominator
X*5X-2*5X-1=0
Wy multiply elements
5X^2-10X-1=0
a = 5; b = -10; c = -1;
Δ = b2-4ac
Δ = -102-4·5·(-1)
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{30}}{2*5}=\frac{10-2\sqrt{30}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{30}}{2*5}=\frac{10+2\sqrt{30}}{10} $
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