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X-3(3X+2)=2(5X-3)
We move all terms to the left:
X-3(3X+2)-(2(5X-3))=0
We multiply parentheses
X-9X-(2(5X-3))-6=0
We calculate terms in parentheses: -(2(5X-3)), so:We add all the numbers together, and all the variables
2(5X-3)
We multiply parentheses
10X-6
Back to the equation:
-(10X-6)
-8X-(10X-6)-6=0
We get rid of parentheses
-8X-10X+6-6=0
We add all the numbers together, and all the variables
-18X=0
X=0/-18
X=0
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