X-3(9+x-3)=x-2(6+x-2)

Solution for X-3(9+x-3)=x-2(6+x-2) equation:

X-3(9+X-3)=X-2(6+X-2)

We move all terms to the left:

X-3(9+X-3)-(X-2(6+X-2))=0

We add all the numbers together, and all the variables

X-3(X+6)-(X-2(X+4))=0

We multiply parentheses

X-3X-(X-2(X+4))-18=0


We calculate terms in parentheses: -(X-2(X+4)), so:

X-2(X+4)

We multiply parentheses

X-2X-8

We add all the numbers together, and all the variables

-1X-8

Back to the equation:

-(-1X-8)


We add all the numbers together, and all the variables

-2X-(-1X-8)-18=0

We get rid of parentheses

-2X+1X+8-18=0

We add all the numbers together, and all the variables

-1X-10=0

We move all terms containing X to the left, all other terms to the right

-X=10

X=10/-1

X=-10