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X-3/10X=105
We move all terms to the left:
X-3/10X-(105)=0
Domain of the equation: 10X!=0We multiply all the terms by the denominator
X!=0/10
X!=0
X∈R
X*10X-105*10X-3=0
Wy multiply elements
10X^2-1050X-3=0
a = 10; b = -1050; c = -3;
Δ = b2-4ac
Δ = -10502-4·10·(-3)
Δ = 1102620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1102620}=\sqrt{4*275655}=\sqrt{4}*\sqrt{275655}=2\sqrt{275655}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1050)-2\sqrt{275655}}{2*10}=\frac{1050-2\sqrt{275655}}{20} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1050)+2\sqrt{275655}}{2*10}=\frac{1050+2\sqrt{275655}}{20} $
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