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X-3/2X=12
We move all terms to the left:
X-3/2X-(12)=0
Domain of the equation: 2X!=0We multiply all the terms by the denominator
X!=0/2
X!=0
X∈R
X*2X-12*2X-3=0
Wy multiply elements
2X^2-24X-3=0
a = 2; b = -24; c = -3;
Δ = b2-4ac
Δ = -242-4·2·(-3)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-10\sqrt{6}}{2*2}=\frac{24-10\sqrt{6}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+10\sqrt{6}}{2*2}=\frac{24+10\sqrt{6}}{4} $
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