If it's not what You are looking for type in the equation solver your own equation and let us solve it.
228;12
228;1
(sin(x)+1)/(2-cos(x))
(sin(x))^2
30 = 5/6
| x+7x=12+9-2 | | 3x+1+x-4=0 | | 2=m-15 | | 5(2x-7)-9(x+4)= | | 5a-2b+4a+5b= | | -5(5+4a)=-23-8a | | 4x^2-6x+22=0 | | 14=m-3 | | m=2(x-1)/(3-x) | | 9x+8=7.2 | | 3+m=21 | | 5(0.25+-0.3z)2z=1.32 | | 5w/4=15 | | M=17 | | -8(4n+7)=-216 | | 0.09xX=92.20 | | X+20=2(x+12) | | X/-416 | | 4x+(9x-1)=180 | | 3s+z=0.75 | | 4x+(9x-1)=90 | | 13/4=39/x | | x-.05x=261.25 | | 13/4=39/n | | 2z+70=4x | | b=13+-1.8(5) | | 3(-x+4)+4(5x+3)=13-x+42 | | 5b^3+15b^2+12v=-36 | | 1/4-x-1/7=x/4 | | X+(x+50)+(2x+50)=750 | | 100=.5*b*20 | | X+(x+50)+2x+50=750 |