X-3/x+2=6/2x+4

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Solution for X-3/x+2=6/2x+4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

X-(3/x)+2 = (6/2)*x+4 // - (6/2)*x+4

X-((6/2)*x)-(3/x)-4+2 = 0

X-3*x-3*x^-1-4+2 = 0

-3*x^1-3*x^-1-2*x^0 = 0

(-3*x^2-2*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(-3*x^2-2*x^1-3*x^0) = 0

x^1

-3*x^2-2*x-3 = 0

-3*x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*(-3)*4)

DELTA = -32

DELTA < 0

x in { } 

x belongs to the empty set

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