X-4/3x+8=0

Solution for X-4/3x+8=0 equation:

X-4/3X+8=0


Domain of the equation: 3X!=0

X!=0/3

X!=0

X∈R


We multiply all the terms by the denominator


X*3X+8*3X-4=0

Wy multiply elements

3X^2+24X-4=0

a = 3; b = 24; c = -4;
Δ = b2-4ac
Δ = 242-4·3·(-4)
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{39}}{2*3}=\frac{-24-4\sqrt{39}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{39}}{2*3}=\frac{-24+4\sqrt{39}}{6}
$