X-4/x+6=2x+3/2x-1

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Solution for X-4/x+6=2x+3/2x-1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

X-(4/x)+6 = 2*x+(3/2)*x-1 // - 2*x+(3/2)*x-1

X-(2*x)-((3/2)*x)-(4/x)+1+6 = 0

X-2*x+(-3/2)*x-4*x^-1+1+6 = 0

7*x^0-7/2*x^1-4*x^-1 = 0

(7*x^1-7/2*x^2-4*x^0)/(x^1) = 0 // * x^2

x^1*(7*x^1-7/2*x^2-4*x^0) = 0

x^1

(-7/2)*x^2+7*x-4 = 0

(-7/2)*x^2+7*x-4 = 0

DELTA = 7^2-(-4*4*(-7/2))

DELTA = -7

DELTA < 0

x in { } 

x belongs to the empty set

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