X-4=-3(-x+4)+8(2x-3)=0

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Solution for X-4=-3(-x+4)+8(2x-3)=0 equation: 



X-4=-3(-X+4)+8(2X-3)=0

We move all terms to the left:

X-4-(-3(-X+4)+8(2X-3))=0

We add all the numbers together, and all the variables

X-(-3(-1X+4)+8(2X-3))-4=0



We calculate terms in parentheses: -(-3(-1X+4)+8(2X-3)), so:

-3(-1X+4)+8(2X-3)

We multiply parentheses

3X+16X-12-24

We add all the numbers together, and all the variables

19X-36

Back to the equation:

-(19X-36)



We get rid of parentheses

X-19X+36-4=0

We add all the numbers together, and all the variables

-18X+32=0

We move all terms containing X to the left, all other terms to the right

-18X=-32

X=-32/-18

X=1+7/9

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