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X-5+2(X-1)=3(X-3)+5
We move all terms to the left:
X-5+2(X-1)-(3(X-3)+5)=0
We multiply parentheses
X+2X-(3(X-3)+5)-2-5=0
We calculate terms in parentheses: -(3(X-3)+5), so:We add all the numbers together, and all the variables
3(X-3)+5
We multiply parentheses
3X-9+5
We add all the numbers together, and all the variables
3X-4
Back to the equation:
-(3X-4)
3X-(3X-4)-7=0
We get rid of parentheses
3X-3X+4-7=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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