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X-5+3X=2X+2(X+3)
We move all terms to the left:
X-5+3X-(2X+2(X+3))=0
We add all the numbers together, and all the variables
4X-(2X+2(X+3))-5=0
We calculate terms in parentheses: -(2X+2(X+3)), so:We get rid of parentheses
2X+2(X+3)
We multiply parentheses
2X+2X+6
We add all the numbers together, and all the variables
4X+6
Back to the equation:
-(4X+6)
4X-4X-6-5=0
We add all the numbers together, and all the variables
-11!=0
There is no solution for this equation
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